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Question
Calculate the molality of a solution containing 7.5 g glycine(NH2-CH2-COOH) dissolved in 500g of water.
Solution
Molality = `"no. of moles of solute"/"mass of solvent (in kg)"`
no. of moles of glycine = `"mass of glycine"/"molar mass of glycine"`
`= 7.5/7.5` = 0.1
Molality = `0.1/(0.5 "kg")` = 0.2 m
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