Advertisements
Advertisements
Question
Calculate the number of water molecules present in one drop of water which weighs 0.18 g.
Solution
One mole of water weighs 18 g.
18 g of water contains 6.023 × 1023 water molecules.
∴ 0.18 g of water contains
= `(6.023×10^23)/18` × 0.18
= 6.023 × 1021 water molecules.
APPEARS IN
RELATED QUESTIONS
Fill in the blank
_______ is a triatomic molecule.
State the term
The symbolic representation of a molecule ______
State the term
A group of atoms that react as a single unit ______.
State the term
The combining capacity of an element _______
If one mole of nitrogen molecules weighs 28 g, calculate the mass of one molecule of nitrogen in grams.
Which contains more molecules, 10 g of sulphur dioxide (SO2) or 10 g of oxygen (O2) ?
(Atomic masses : S = 32 u ; O = 16 u)
What is the number of electrons donated by a magnesium atom and number of electrons accepted by a sulphur atom during their chemical combination?
Diagrammatically represent the transfer of electrons.
Explain the term ‘atomicity’.
State the correct formula of the following from the option given:
Copper [II] nitrate
