Question

Calculate the orbital magnetic dipole moment of the electron in the second Bohr orbit of the hydrogen atom, given the radius of the orbit is 2.1 Å and the orbital speed is 1.1 × 10⁶ m/s.

Answer 1

Data: r = 2.1 Å = 2.1 × 10⁻¹⁰ m, v = 1.1 × 10⁶ m/s, e = 1.6 × 10⁻¹⁹ C

The orbital magnetic dipole moment of the electron,

`M_0 = 1/2 ever`

= `1/2 (1.6 xx 10^-19) (1.1 xx 10^6) (2.1 xx 10^-10)`

= 0.8 × 2.31 × 10⁻²³

= 1.848 × 10⁻²³ A.m³