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Question
Calculate the pH of the resultant mixtures: 10 mL of 0.01M H2SO4 + 10 mL of 0.01M Ca(OH)2.
Solution
Moles of `"H"_3"O"^+ = (2xx 10 xx 0.01)/1000` = .0002 mol
Moles of `"OH"^- = (2xx10xx 0.01)/1000 = .0002 "mol"`
Since there is neither an excess of `"H"_3"O"^ or "OH"^-`, the solution is neutral. Hence, pH = 7.
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