Question

Calculate the work done during compression of 2 mol of an ideal gas from a volume of 1m³ to 10 dm³ 300K against a pressure of 100 KP a.

Options

• - 99 kJ

• + 99 kJ

• + 22.98 kJ

• - 22.98 kJ

Answer 1

+ 99 kJ

Explanation:

Work done during compression,

W = p_ext ΔV

Given, p_ext = 100 KPa, T = 300 K

ΔV = V₂ - V₁

= (10 - 1)dm³ = 9 dm³

= 0.99 m³

∴ W = 100 KPa (0.99) m³

= 99 kJ