Question

Calculated the mole fraction of benzene in a solution containing 30% by mass of its is carbon tetrachloride

Options

• 0.459

• 0.192

• 0.716

• 0.818

Answer 1

0.459

Explanation:

Let the start 100 g of the So in which mass of benzene = 30 g

Mass of carbon tetrachloride = 70 g

Molar mass of benzene (COH₆) = 6 × 12 + 6 × 1 = 78 g mol^–1 

Molar mass of tetrachlorid = (Cd^–4) = 12 + 4 × 35.5 = 154 g mol^–1 

mccl4 = 70 g/154 g mol^–1 = 0.454 mol

xC₆H₆ = MC₆H₆/MC₆H₆ + MCCl₄

= `0.385/((0.385  mol) + (0.454  mol))`

= 0.459 mol.