Advertisements
Advertisements
Question
Capacitor plates are charged by a battery with ‘V’ volts. After charging the battery is disconnected and a dielectric slab with dielectric constant ‘K’ is inserted between its plates, the potential across the plates of a capacitor will become ____________.
Options
Zero
V/2
V/K
KV
MCQ
Fill in the Blanks
Solution
Capacitor plates are charged by a battery with ‘V’ volts. After charging the battery is disconnected and a dielectric slab with dielectric constant ‘K’ is inserted between its plates, the potential across the plates of a capacitor will become V/K.
Explanation:
The battery is disconnected
Q = Charge remains context
Cʹ = K C
Qʹ = Cʹ Vʹ
Q = Cʹ Vʹ
Q = K C Vʹ
`"V'" = "Q"/("K C") = "V"/"K"`
shaalaa.com
Is there an error in this question or solution?
