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CHA3−CHA2−CHO→alkaliDilProduct The product in the above reaction is: -

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Question

\[\ce{CH3-CH2-CHO ->[dil][alkali] Product}\]

The product in the above reaction is:

Options

  • CH3–CH2COOH

  • CH3–CH2–CH2OH

  • \[\begin{array}{cc}
    \ce{CH3-CH2-CH-CH2-CHO}\\
    |\phantom{...}\\
    \ce{OH}\phantom{.}
    \end{array}\]

  • \[\begin{array}{cc}
    \phantom{............}\ce{CH3}\\
    \phantom{.........}|\\
    \ce{CH3-CH2-CH-CH-CHO}\\
    |\phantom{..}\\
    \ce{OH}
    \end{array}\]

MCQ

Solution

\[\begin{array}{cc}
\phantom{............}\ce{CH3}\\
\phantom{.........}|\\
\ce{CH3-CH2-CH-CH-CHO}\\
|\phantom{..}\\
\ce{OH}
\end{array}\]

Explanation:

\[\begin{array}{cc}\\
\phantom{......................................................}\ce{CH3}\\
\phantom{...................................................}|\\
\ce{CH3-CH2-C-H + CH3-CH-CHO ->[dil][alkali] CH3-CH2-CH-CH-C-H}\\
\phantom{...........}||\phantom{.............}|\phantom{............................}||\phantom{..........}|\phantom{...}\\
\phantom{..............}\ce{O}\phantom{............}\ce{H}\phantom{...........................}\ce{OH}\phantom{........}\ce{O}\phantom{.....}
\end{array}\]

This reaction is called Aldol Reaction.

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