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CHA3CHA2COOH→red PClA2A→alc⋅KOHB. What is B? -

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Question

\[\ce{CH3CH2COOH ->[Cl2][red P] A ->[alc. KOH] B}\]. What is B?

Options

  • \[\ce{CH3CH2COCl}\]

  • \[\ce{CH3CH2CHO}\]

  • \[\ce{CH2 = CHCOOH}\]

  • \[\ce{ClCH2CH2COOH}\]

MCQ

Solution

\[\ce{CH2 = CHCOOH}\]

Explanation:

\[\ce{CH3CH2COOH ->[Cl2][red P] CH3CHClCOOH ->[alc. KOH][- HCl] CH2 = \underset{Acrylic acid}{CHCOOH}}\]

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