Question

छेदाचे परिमेयीकरण करा.

${\displaystyle \frac{12}{4\sqrt{3}-\sqrt{2}}}$

Answer 1

${\displaystyle \frac{12}{4\sqrt{3}-\sqrt{2}}}$

= ${\displaystyle \frac{12}{4\sqrt{3}-\sqrt{2}}\times \frac{4\sqrt{3}+\sqrt{2}}{4\sqrt{3}+\sqrt{2}}}$

= ${\displaystyle \frac{12(4\sqrt{3}+\sqrt{2})}{{\left(4\sqrt{3}\right)}^2-{\left(\sqrt{2}\right)}^2}}$   ...[(a + b) (a - b) = a² - b²]

= ${\displaystyle \frac{12(4\sqrt{3}+\sqrt{2})}{48-2}}$

= ${\displaystyle \frac{12(4\sqrt{3}+\sqrt{2})}{46}}$

= ${\displaystyle \frac{6(4\sqrt{3}+\sqrt{2})}{23}}$