Question

Choose the correct alternative:

If `"a"_1/x + "b"_1/y = "c"_1, "a"_2/x + "b"_2/y = "c"_2, Delta_1 = |("a"_1, "b"_1),("a"_2, "b"_2)|, Delta_2 = |("b"_1, "c"_1),("b"_2, "c"_2)| Delta_3 = |("c"_1, "a"_1),("c"_2, "a"_2)|` then (x , y) is

Options

• `(Delta_2/Delta_1, Delta_3/Delta_1)`

• `(Delta_3/Delta_1, Delta_2/Delta_1)`

• `(Delta_1/Delta_2, Delta_1/Delta_3)`

• `((-Delta_1)/Delta_2, (-Delta_1)/Delta_3)`

Answer 1

`((-Delta_1)/Delta_2, (-Delta_1)/Delta_3)`