Advertisements
Advertisements
Question
Choose the correct answer from the given four options :
If one root of a quadratic equation with rational coefficients is `(3 - sqrt(5))/(2)`, then the other
Options
`(-3 - sqrt(5))/(2)`
`(-3 + sqrt(5))/(2)`
`(3 + sqrt(5))/(2)`
`(sqrt(3) + 5)/(2)`
Solution
One root of a quadratic equation is `(3 - sqrt(5))/(2)`
then other root will be `(3 + sqrt(5))/(2)`.
APPEARS IN
RELATED QUESTIONS
In the following, determine whether the given values are solutions of the given equation or not:
`x^2 - 3sqrt3x+6=0`, `x=sqrt3`, `x=-2sqrt3`
If x = -3 and x = 2/3 are solutions of quadratic equation mx2 + 7x + n = 0, find the values of m and n
Solve `((2x - 3)/(x -1)) - 4((x - 1)/(2x - 3)) = 3`
Solve: (2x+3)2 = 81
Find the quadratic equation, whose solution set is:
`{−3, (−2)/5}`
Find the value of x, if a+1=0 and `x^2 + ax – 6 = 0`
`x^2-2ax(4b^2-a^2)=0`
Solve:
`x/3 + 3/(6 - x) = (2(6 +x))/15; (x ≠ 6)`
If x = −3 and x = `2/3` are solutions of quadratic equation mx2 + 7x + n = 0, find the values of m and n.
Find whether the value x = `(1)/(a^2)` and x = `(1)/(b^2)` are the solution of the equation:
a2b2x2 - (a2 + b2) x + 1 = 0, a ≠ 0, b ≠ 0.