Advertisements
Advertisements
Question
Choose the correct option:
A parallel plate capacitor is charged and then isolated. The effect of increasing the plate separation on charge, potential, capacitance respectively are ______.
Options
Constant, decreases, decreases
Increases, decreases, decreases
Constant, decreases, increases
Constant, increases, decreases
Solution
A parallel plate capacitor is charged and then isolated. The effect of increasing the plate separation on charge, potential, capacitance respectively are Constant, increases, decreases.
Explanation:
The charge on the capacitor stays constant because it is separated after charging. Capacitance reduces as plate separation increases because C = `(epsilon_0"A")/"d"`, and as a result, potential rises because V = `"q"/"C"`.
RELATED QUESTIONS
Answer in brief:
If the difference between the radii of the two spheres of a spherical capacitor is increased, state whether the capacitance will increase or decrease.
Answer in brief:
A spherical shell of radius b with charge Q is expanded to a radius a. Find the work done by the electrical forces in the process.
Choose the correct:
Charge + q and - q are placed at points A and B respectively which are distance 2L apart. C is the midpoint of A and B. The work done in moving a charge + Q from C to D, along the semicircle CD as shown in the figure below, is ______.
The work done in carrying a charge Q once round a circle of radius r with charge q at the centre of the circle is ______
The mean free path of electrons in a metal is 4 x 10-8m. Find the electric field, in units of V/m, which can give on an average 2 eV energy to an electron in the metal.
Obtain an expression for the electric field intensity at a point outside uniformly charged infinite plane sheet.
Obtain an expression for the capacitance of a parallel plate capacitor without a dielectric.
