Advertisements
Advertisements
Question
Choose the correct option.
In the spectrum of the hydrogen atom which transition will yield the longest wavelength?
Options
n = 2 to n = 1
n = 5 to n = 4
n = 7 to n = 6
n = 8 to n = 7
Solution
n = 8 to n = 7
Explanation:
The eighth energy level, E8 = – 0.2125
The seventh energy level, E7 = – 0.277
E8 – E7 = 0.06
RELATED QUESTIONS
If the number of nuclei in a radioactive sample at a given time is N, what will be the number at the end of two half-lives?
Answer in brief.
Define the Excitation energy of an electron in an atom.
Define the Binding energy of an electron in an atom.
Define ionization energy of an electron in an atom.
Starting from the formula for the energy of an electron in the nth orbit of the hydrogen atom, derive the formula for the wavelengths of Lyman and Balmer series spectral lines and determine the shortest wavelengths of lines in both these series.
Choose the correct option.
The radius of the 4th orbit of the electron will be smaller than its 8th orbit by a factor of ______.
Which of the following properties of a nucleus does not depend on its mass number?
When an electron jumps from a higher energy orbit to a lower energy orbit, the difference in the energies in the two orbits is radiated as quantum (photon) of ______
The ionization energy of Hydrogen atom in its ground state is ______.
The ratio of areas of the circular orbit of an electron in the ground state to that of the first excited state of an electron in a hydrogen atom is ______
What is the angular momentum of an electron in the first excited state for a hydrogen atom?
In which region of the electromagnetic spectrum for Hydrogen, does the Lyman series lies?
How much energy must be supplied to a hydrogen atom, to free (remove) the electron in the ground state?
State the value of minimum excitation energy for the Hydrogen atom.
Define: Ionization energy.
Draw a neat labelled diagram showing energy levels and transition between them for the hydrogen atoms.
Using the expression for the energy of an electron in the nth orbit, Show that `1/lambda = "R"_"H"(1/"n"^2 - 1/"m"^2),` Where symbols have their usual meaning.
