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Question
Choose the correct relation between polarization 'P' and electric susceptibility 'Xe' of dielectric material. (E = electric field)
Options
P = `"Xe"/"E"^2`
P = `"Xe"/"E"`
P = XeE
P = `"X"_"e"^2 "E"`
MCQ
Solution
P = XeE
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Dielectrics and Electric Polarisation
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