Question

$$\begin{array}{c}\mathrm{CH}{\phantom{A}}_3-\mathrm{CH}{\phantom{A}}_2-\mathrm{CH}-\mathrm{CH}{\phantom{A}}_3\\ \phantom{.....}|\\ \phantom{......}\mathrm{Cl}\end{array}$$  obtained by chlorination of n-butane, will be

Options

• ${\displaystyle l}$ - form

• d - form

• Meso form

• Racemic mixture

Answer 1

Racemic mixture

Explanation:

Chlorination ofn-butane takes place via free radical formation i.e., $$\mathrm{Cl}{\phantom{A}}_2\stackrel{\mathrm{hv}}{\to }\mathrm{C}\stackrel{\bullet }{\mathrm{l}}+\mathrm{C}\stackrel{\bullet }{\mathrm{l}}$$

$$\mathrm{C}\stackrel{\bullet }{\mathrm{l}}$$ may attack on either side and give a racemic mixture of 2-chlorbutane which contain 50% d - form and 50% ${\displaystyle l}$ - form.