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CHX3CHX2CHX2Cl→alc⋅KOHB→HBrC→Na/etherD In the above reaction, the product D is: -

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Question

\[\ce{CH3CH2CH2Cl ->[alc. KOH] B ->[HBr] C ->[Na/ether] D}\]

In the above reaction, the product D is:

Options

  • Propane

  • 2, 3-Dimethylbutane

  • Hexane

  • Allyl bromide

MCQ

Solution

2, 3-Dimethylbutane

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