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Question
Column I | Column II |
(i) The additive inverse of +2 | (A) 0 |
(ii) The greatest negative integer | (B) –2 |
(iii) The greatest negative even integer | (C) 2 |
(iv) The smallest integer greater than every negative integer | (D) 1 |
(v) Sum of predecessor and successor of –1 | (E) –1 |
Solution
Column I | Column II |
(i) The additive inverse of +2 | (B) –2 |
(ii) The greatest negative integer | (E) –1 |
(iii) The greatest negative even integer | (B) –2 |
(iv) The smallest integer greater than every negative integer | (A) 0 |
(v) Sum of predecessor and successor of –1 | (B) –2 |
Explanation:
(i) The additive inverse of +2 is –2.
(ii) The greatest negative integer is –1.
(iii) The greatest negative even integer is –2.
(iv) The smallest integer 0 is greater than every negative integer.
(v) Predecessor and successor of –1 are –2 and 0 respectively.
∴ Sum = –2 + 0 = –2
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