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Question
Compute the heat generated while transferring 96000 coulomb of charge in one hour through a potential difference of 50 V.
Solution
Given Charge, Q = 96000C
Time, t = 1hr = 60 x 60 = 3600s
Potential difference, V= 50volts
Now we know that H = VIt
So we have to calculate I first
As I = `Q/t`
∴ I = `96000/3600`
= `80/3A`
H = V × I × t
By substituting the values,
`50 xx 80/3 xx 60 xx 60`
= 4.8 × 106 J
Therefore, the heat generated is 4.8 × 106 J.
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