Question

Conant Finkelstein reaction for the preparation of alkyl iodide is based upon the fact that:

Options

• Sodium iodide is soluble in methanol, while sodium chloride is insoluble in methanol.

• Sodium iodide is soluble in methanol, while NaCl and NaBr are insoluble in methanol.

• Sodium iodide is insoluble in methanol, while NaCl and NaBr are soluble.

• The three halogens differ considerably in their electronegativity.

Answer 1

Sodium iodide is soluble in methanol, while NaCl and NaBr are insoluble in methanol.