Question

Consider

Statement 1: (p∧∼q) ∧ (∼p ∧ q) is a fallacy.

Statement 2: (p→q) ↔ (∼q→∼p) is a tautology.

Options

• Statement-1 is true; Statement-2 is true; Statement-2 is a correct explanation for Statement-1

• Statement-1 is true; Statement-2 is true; Statement-2 is not a correct explanation for Statement-1

• Statement-1 is true; Statement-2 is false

• Statement-1 is false; Statement-2 is true

Answer 1

Statement-1 is true; Statement-2 is true; Statement-2 is not a correct explanation for Statement-1

Explanation:

Statement-1: (p∧∼q) ∧ (∼p ∧ q)

= p ∧∼p ∧∼q ∧ q

= f ∧ f

⇒ f

So, statement–1 is true

Statement-2: = (p→q) ↔ (p→q)

Which is always true

So, Statement –2 is true