Question

Consider the following reaction:

\[\ce{xMnO^-_4 + yC2O^{2-}_4 + zH^+ -> xMn^{2+} + 2{y}CO2 + z/2H2O}\]

The values of x, y, and z in the reaction are, respectively:

Options

• 5, 2 and 16

• 2, 5 and 8

• 2, 5 and 16

• 5, 2 and 8

Answer 1

2, 5 and 16

Explanation:

On balancing the given equations, we get

\[\ce{2MnO^-_4 + 5C2O^{2-}_4 + 16H^+ -> 2Mn^{2+} + 10CO2 + 8H2O}\]

So, x = 2, y = 5 and z = 16.