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Question
Consider the two sets : A = {m ∈ R : both the roots of x2 – (m + 1)x + m + 4 = 0 are real} and B = [–3, 5). Which of the following is not true?
Options
A – B = (–∞, –3) ∪ [5, ∞)
A ∩ B = {–3}
B – A = (–3, 5)
A ∪ B = R
MCQ
Solution
A – B = (–∞, –3) ∪ [5, ∞)
Explanation:
A = {m ∈ R : x2 – (m + 1)x + m + 4 = 0 has real roots}
D ≥ 0
⇒ (m + 1)2 – 4(m + 4) ≥ 0
⇒ m2 – 2m – 15 ≥ 0
A = {(–∞, –3] ∪ [5, ∞)}
B = [–3, 5)
⇒ A – B = (–∞, –3) ∪ [5, ∞)
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Solution of Linear Inequality
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