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Construct a Square Abcd, When: Perimeter = 24 Cm - Mathematics

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Question

Construct a square ABCD, when: Perimeter = 24 cm.

Sum

Solution

The perimeter of a square
P = 4a
Where a is the length of each side
We have Perimeter = 24 cm
Therefore,
24 = 4a 
4 =6
Therefore the sides of the squares are of length 6 cm. 

Steps:

1. Draw a line segment Ab = 6cm.

2. Draw AP ⊥ AB.

3. From AP cut off AD = 6cm.

4. With B as a center and radius, 6 cm draw an arc.

5. With D as center and radius, 6 cm draw another arc cutting the former arc at C.

6. Join BC and CD.

ABCD is the required square.

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Construction of Square
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Chapter 15: Construction of Polygons (Using ruler and compass only) - Exercise 15 [Page 190]

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Selina Concise Mathematics [English] Class 9 ICSE
Chapter 15 Construction of Polygons (Using ruler and compass only)
Exercise 15 | Q 30 | Page 190
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