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Construct a Quadrilateral Pqrs, in Which ∠Q = 45°, ∠R = 90°, Qr = 5 Cm, Pq = 9 Cm and Rs = 7 Cm. - Mathematics

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Question

Construct a quadrilateral PQRS, in which ∠Q = 45°, ∠R = 90°, QR = 5 cm, PQ = 9 cm and Rs = 7 cm.

Answer in Brief

Solution

Steps of construction: 

Step I: Draw QR = 5 cm . 

Step II: Construct ∠PQR = 45° at Q . 

Step III : With Q as the centre and radius 9 cm, cut off QP = 9 cm . 

Step IV: Construct ∠QRS = 90° at R . 

Step V : With R as the centre and radius 7 cm, cut off RS = 7 cm . 

Since, the line segment PQ and RS intersect each other, the quadrilateral cannot be constructed .

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Chapter 18: Practical Geometry (Constructions) - Exercise 18.4 [Page 11]

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RD Sharma Mathematics [English] Class 8
Chapter 18 Practical Geometry (Constructions)
Exercise 18.4 | Q 6 | Page 11
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