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Question
Copper crystallises with fee unit cell. If the radius of copper atom is 127.8 pm, calculate the density of copper? (At. mass: Cu = 63.55 g mol-1)
Options
9.5 g cm-3
1.89 g cm-3
4.4 g cm-3
8.9 g cm-3
MCQ
Solution
8.9 g cm-3
Explanation:
`rho = "nM"/("a"^3"N"_"a")`
`"4r"/sqrt2` = a
∴ a = `(4 xx 1.278 xx 10^-8 "cm")/sqrt2`
a = 3.615 × 10-8 cm
a3 = 47.25 × 10-24 cm
∴ `rho = (4 xx 63.55)/(47.25 xx 10^-24 xx 6.022 xx 10^23)`
`= 254.2/28.45`
= 8.934 g cm-3
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