Advertisements
Advertisements
Question
`cos^-1 (cos (4pi)/3)` = ______.
Options
\[\frac{5\pi}{6}\]
\[\frac{\pi}{3}\]
\[\frac{4\pi}{3}\]
\[\frac{2\pi}{3}\]
MCQ
Solution
`cos^-1 (cos (4pi)/3)` = \[\underline{\frac{2\pi}{3}}\]
Explanation:
`cos^-1 (cos (4pi)/3)`
`= cos^-1 {cos (pi + pi/3)}`
`= cos^-1 (- cos pi/3)`
`= pi - cos^-1 (cos pi/3)` ....[∵ cos-1 (- x) = π - cos-1 x]
`= pi - pi/3 = (2pi)/3`
shaalaa.com
Trigonometric Equations and Their Solutions
Is there an error in this question or solution?