Question

`(("cos"  30  theta + "i" "sin" 30  theta)^5 ("cos"  20  theta + "i"  "sin" 20 theta)^4)/(("cos"  theta + "i"  "sin"  theta)^-4("cos"  theta  "i"   "sin"  theta)^6)` is equal to:

Options

• Cos 27 θ − i sin 27 θ

•  cos 33 θ - i sin 33 θ

• cos 33 θ + i sin 33 θ

• cos 27 θ + i sin 27 θ

Answer 1

cos 33 θ + i sin 33 θ