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Question
`"cos"^-1 ["cos" (2 "cot"^-1 (sqrt2 - 1))] =` ____________.
Options
`sqrt2 - 1`
`1 + sqrt2`
`pi/4`
`(3 pi)/4`
MCQ
Fill in the Blanks
Solution
`"cos"^-1 ["cos" (2 "cot"^-1 (sqrt2 - 1))] =` `underline((3 pi)/4)`.
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