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Costansincotxcos[tan-1{sin(cot-1x)}] is equal to ____________. -

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Question

`"cos" ["tan"^-1 {"sin" ("cot"^-1 "x")}]` is equal to ____________.

Options

  • `sqrt(("x"^2 + 2)/("x"^3 + 3))`

  • `sqrt(("x"^2 + 2)/("x"^2 + 1))`

  • `sqrt(("x"^2 + 1)/("x"^2 + 2))`

  • None of these

MCQ
Fill in the Blanks

Solution

`"cos" ["tan"^-1 {"sin" ("cot"^-1 "x")}]` is equal to `underline(sqrt(("x"^2 + 1)/("x"^2 + 2))`.

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