Question

\[\begin{array}{cc}
\ce{D}\phantom{........................}\\
|\phantom{.........................}\\
\ce{2D - C = O + OH^- ->[Cannizzaro] X and Y}
\end{array}\]

(Y is alcohol, D is deuterium)

X and Y will have the structure:

Options

• \[\begin{array}{cc}
  \phantom{.}\ce{D}\phantom{..........}\ce{O}\phantom{..}\\
  \phantom{.}|\phantom{...........}||\phantom{..}\\
  \ce{D - C - \overset{–}{O}, D - C - OH}\\
  |\phantom{..............}\\
  \ce{H}\phantom{..............}
  \end{array}\]

• \[\begin{array}{cc}
  \phantom{.}\ce{D}\phantom{..........}\ce{O}\phantom{..}\\
  \phantom{.}|\phantom{...........}||\phantom{..}\\
  \ce{D - C - \overset{–}{O}, D - C - OH}\\
  |\phantom{..............}\\
  \ce{D}\phantom{..............}
  \end{array}\]

• \[\begin{array}{cc}
  \phantom{.}\ce{O}\phantom{..........}\ce{D}\phantom{..}\\
  \phantom{}||\phantom{...........}|\phantom{..}\\
  \ce{H - C - \overset{–}{O}, D - C - OH}\\
  \phantom{..........}|\\
  \phantom{..........}\ce{D}
  \end{array}\]

• None is correct

Answer 1

None is correct

Explanation:

Step I:

Step II: 

Step III: 

\[\begin{array}{cc}
\phantom{}\ce{O}\phantom{.........................}\ce{O}\phantom{...................}\\
\phantom{}||\phantom{..........................}||\phantom{...................}\\
\ce{D - C - OH + CD3O ->[Na^+][fast] D - C - O^- + Na^+ + CD3OH}
\end{array}\]