Question

Daily requirement of energy of a person is 'x' kJ. If heat of combustion of food material (Molecular mass = 100 g) is 'y' kJ, his daily consumption of the food in gram would be ____________.

Options

• `"x"/"y"`

• `("x"/"y") xx 100`

• `("y"/"x") xx 100`

• `"y"/"x"`

Answer 1

Daily requirement of energy of a person is 'x' kJ. If heat of combustion of food material (Molecular mass = 100 g) is 'y' kJ, his daily consumption of the food in gram would be `underline(("x"/"y") xx 100)`.

Explanation:

∆H_c for food material = y kJ.

Thus, y kJ energy is obtained from 100 g food.

∴ x kJ energy will be obtained from

`100/"y" xx "x g food"`

∴ Daily consumption of food = `"x"/"y" xx 100`