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Question
`"d"/"dx"`[cos (3x + 2)] = ?
Options
sin (2x + 3)
2 sin (3x + 2)
- sin (2x + 3)
- 3 sin (3x + 2)
MCQ
Solution
- 3 sin (3x + 2)
Explnataion:
`"d"/"dx"`[cos (3x + 2)]
= - sin (3x + 2) `"d"/"dx"`(3x + 2)
= - 3 sin (3x + 2)
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Solution of a Differential Equation
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