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Ddxxlogx = ______. -

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Question

`d/(dx)x^(logx)` = ______.

Options

  • `x^(logx)((2logx)/x)`

  • `x^(logx) (2logx)`

  • `x^(logx)(logx/x)`

  • `x^(logx)(logx)`

MCQ
Fill in the Blanks

Solution

`d/(dx)x^(logx)` = `underlinebb(x^(logx)((2logx)/x))`.

Explanation:

y = `x^(logx)`

y' = `logx(x)^(logx-1) + (x^(logx) logx)/x`

= `(2logx  x^(logx))/x`

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