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Delegates from 24 countries participate in a round table discussion. Find the number of seating arrangements where two specified delegates are never together. - Mathematics and Statistics

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Question

Delegates from 24 countries participate in a round table discussion. Find the number of seating arrangements where two specified delegates are never together.

Sum

Solution

When 2 specified delegates are never together then, the other 22 delegates can participate in a round table discussion in (22  1)! = 21! ways.
∴ There are 22 places of which any 2 places can be filled by those 2 delegates who are never together.
∴ Two specified delegates can be arranged in 22P2 ways.
∴ Total number of arrangements if two specified delegates are never together
= `""^22"P"_2xx21!`

= `(22!)/((22-2)!)xx21!`

= `(22!)/(20!)xx21!`
= 22 × 21 × 21!
= 21 × 22 × 21!
 = 21 × 22!

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Permutations - Properties of Permutations
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Chapter 6: Permutations and Combinations - Exercise 6.5 [Page 85]

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Balbharati Mathematics and Statistics 2 (Commerce) [English] 11 Standard Maharashtra State Board
Chapter 6 Permutations and Combinations
Exercise 6.5 | Q 3. (ii) | Page 85

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