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Question
Derive a Canonical POS expression for a Boolean function G, represented by the following truth table:
| X | Y | Z | G(X, Y, Z) |
| 0 | 0 | 0 | 0 |
| 0 | 0 | 1 | 0 |
| 0 | 1 | 0 | 1 |
| 0 | 1 | 1 | 0 |
| 1 | 0 | 0 | 1 |
| 1 | 0 | 1 | 1 |
| 1 | 1 | 0 | 0 |
| 1 | 1 | 1 | 1 |
Solution
Canonical POS expression for a Boolean function G
`=(X + Y + Z)(X + Y + bar(Z))(X + bar(Y) + bar(Z))(bar(X) + bar(Y) + Z)`
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Obtaining Sum of Product (SOP) and Product of Sum (POS) Form the Truth Table
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