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Derive mathematically value of KP for AX(g)+BX(g)↽−−⇀CX(g)+DX(g). - Chemistry

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Question

Derive mathematically value of KP for \[\ce{A_{ (g)} + B_{ (g)} ⇌ C_{ (g)} + D_{ (g)}}\].

Short Note

Solution

When the concentrations of reactants and products in gaseous reactions are expressed in terms of their partial pressure, then the equilibrium constant is represented as KP.

∴ For the reaction,

\[\ce{A_{ (g)} + B_{ (g)} ⇌ C_{ (g)} + D_{ (g)}}\]

the equilibrium constant (KP) can be expressed using partial pressure as: KP = `("P"_"C" xx "P"_"D")/("P"_"A" xx "P"_"B")`

Where PA, PB, PC and PD are equilibrium partial pressures of A, B, C and D respectively.

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Law of Mass Action and Equilibrium Constant
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Chapter 12: Chemical Equilibrium - Exercises [Page 189]

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Balbharati Chemistry [English] 11 Standard
Chapter 12 Chemical Equilibrium
Exercises | Q 2. (C) | Page 189
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