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Tamil Nadu Board of Secondary EducationHSC Science Class 12

Determine the number of positive and negative roots of the equation x9 – 5x8 – 14x7 = 0 - Mathematics

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Question

Determine the number of positive and negative roots of the equation x9 – 5x8 – 14x7 = 0

Sum

Solution

x9 – 5x8 – 14x7 = 0

P(x) = x9 – 5x8 – 14x7.

The number of sign changes is P(x) is 1.

The number of positive roots is 1.

P(– x) = – x9 – 5x8 + 14x7

The number of sign changes is P(– x) is one.

The number of negative zero of P(– x) is 1.

It is clear that 0 is a root of the equation.

∴ The number of the imaginary roots is at least 6.

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Chapter 3: Theory of Equations - Exercise 3.6 [Page 127]

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Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 12 TN Board
Chapter 3 Theory of Equations
Exercise 3.6 | Q 4 | Page 127
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