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Question
Determine the standard error of proportion for a random sample of 500 pineapples was taken from a large consignment and 65 were found to be bad
Solution
Sample size n = 500
No. of bad pine apples = 65
Sample proportion = P = `65/100` = 0.13
Q = 1 – p
⇒ Q = 1 – 0.13
∴ Q = 0.87
The S.E for sample proportion is given by
S.E = `sqrt("PQ"/"N")`
= `sqrt(((0.13)(0.87))/500)`
= `sqrt(0.1131/500`
= `sqrt(0.0002262)`
= 0.01504
∴ S.E = 0.015
Hence the standard error for sample proportion is S.E = 0.015
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