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Dimensions of ε0 εdϕεdt are of -

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Question

Dimensions of ε0 `(d phi_ε)/(dt)` are of

Options

  • Potential

  • Charge

  • Capacitance

  • Current

MCQ

Solution

Current

Explanation:

`(ε_0d phi_ε)/(dt) = (ε_0 EA)/(dt  4piε_0 r^2)`

= `(M^-1L^-3T^4A^2)/(M^-1L^-3A^2) xx (A^1T^1)/L^2 xx L^2/T`

= A = Current

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