Advertisements
Advertisements
Question
Dimensions of ‘resistance’ are same as (where h is Planck's constant and e is charge):
Options
`"h"/"e"`
`"h"^2/"e"`
`"h"/"e"^2`
`"h"^2/"e"^2`
MCQ
Solution
`"h"/"e"^2`
Explanation:
`"h"/"e"^2 = ("ML"^2"T"^-1)/("AT")^2` = ML2T−3A−2 = Resistance (ohm)
shaalaa.com
Is there an error in this question or solution?