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Dimethylamine+Benzoyl chloride→Pyridine? Product formed is: -

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Question

\[\ce{Dimethylamine + Benzoyl chloride ->[Pyridine] ?}\]

Product formed is:

Options

  • N, N-dimethylbenzamide

  • N, N-dimethylacetamide

  • N-phenylbenzamide

  • N-methylbenzamide

MCQ

Solution

N, N-dimethylbenzamide

Explanation:

\[\begin{array}{cc}
\phantom{.........}\ce{O}\phantom{...........................}\ce{O}\phantom{.}\\
\phantom{..........}||\phantom{............................}||\phantom{..}\\
\ce{\underset{Dimethylamine Benzoyl chloride}{(CH3)2-NH + C6H5 - C - Cl} ->[Pyridine][\Delta] \underset{N, N-Dimethylbenzamide}{(CH3)2 - N - C - C6H5} + HCl}
\end{array}\]

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