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Dinesh Went from Place a to Place B and from There to Place C. a is 7.5 Km from B and B is 12.7 Km from C. Ayub Went from Place a to Place D and from There to Place C. D is 9.3 Km from a and C is 11.8 Km from D. Who Travelled More and by How Much? - Mathematics

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Question

Dinesh went from place A to place B and from there to place C. A is 7.5 km from B and B is 12.7 km from C. Ayub went from place A to place D and from there to place C. D is 9.3 km from A and C is 11.8 km from D. Who travelled more and by how much?

Solution

Distance travelled by Dinesh = AB + BC = (7.5 + 12.7) km

Therefore, Dinesh travelled 20.2 km.

Distance travelled by Ayub = AD + DC = (9.3 + 11.8) km

Therefore, Ayub travelled 21.1 km.

Hence, Ayub travelled more distance.

Difference = (21.1 − 20.2) km

Therefore, Ayub travelled 0.9 km more than Dinesh.

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Chapter 2: Fractions and Decimals - Exercise 2.5 [Page 48]

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NCERT Mathematics [English] Class 7
Chapter 2 Fractions and Decimals
Exercise 2.5 | Q 7 | Page 48
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