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Question
Discuss the nature of the roots of the following quadratic equations : `3x^2 - 4sqrt(3)x + 4` = 0
Solution
`3x^2 - 4sqrt(3)x + 4` = 0
Here a = 3, b = `-4sqrt(3)`, c = 4
∴ D = b2 - 4ac
= `(-4sqrt(3))^2 - 4 xx 3 xx 4`
= 48 - 48
= 0
∵ D = 0
∴ Roots are real and equal.
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