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Tamil Nadu Board of Secondary EducationHSC Science Class 12

Dissociation constant of NH4OH is 1.8 × 10−5 the hydrolysis constant of NH4Cl would be ____________. - Chemistry

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Question

Dissociation constant of NH4OH is 1.8 × 10−5 the hydrolysis constant of NH4Cl would be ____________.

Options

  • 1.8 × 10−19

  • 5.55 × 10−10

  • 5.55 × 10−5

  • 1.80 × 10−5

MCQ
Fill in the Blanks

Solution

Dissociation constant of NH4OH is 1.8 × 10−5 the hydrolysis constant of NH4Cl would be 5.55 × 10−10.

Explanation:

Kh = `("K"_"w")/("K"_"b") = (1 xx 10^-14)/(1.8 xx 10^-5)`

= 0.55 × 10−9

= 5.5× 10−10

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Ionic Equilibria - Salt Hydrolysis
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Chapter 8: Ionic Equilibrium - Evaluation [Page 30]

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Samacheer Kalvi Chemistry - Volume 1 and 2 [English] Class 12 TN Board
Chapter 8 Ionic Equilibrium
Evaluation | Q 23. | Page 30
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