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Distance between the planes :- 2x+3y+4z=4 and 4x+6y+8z=12 is -

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Question

Distance between the planes :- 

`2x + 3y + 4z = 4` and `4x + 6y + 8z = 12` is

Options

  • 2 units

  • 4 units

  • 8 units

  • `2/sqrt(29)` units

MCQ

Solution

`2/sqrt(29)` units

Explanation:

Equation of planes are,

`2x + 3y + 4z` = 4  ......(i)

`4x + 6y + 8z` = 12  ......(ii)

Dividing equation (2) by (2)

`2x + 3y + 4z` = 6

The distance between parallel planes  ......(iii)

`ax + by + cz = d_1` and `ax + by + cz = d_1`

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