Advertisements
Advertisements
Question
Divide 24a3b3 by −8ab.
Solution
\[\frac{24 a^3 b^3}{- 8ab}\]
\[ = \frac{24 \times a \times a \times a \times b \times b \times b}{- 8 \times a \times b}\]
\[ = - 3 a^{(3 - 1)} b^{(3 - 1)} \]
\[ = - 3 a^2 b^2\]
APPEARS IN
RELATED QUESTIONS
Divide the given polynomial by the given monomial.
(5x2 − 6x) ÷ 3x
Divide x4 − 2x3 + 2x2 + x + 4 by x2 + x + 1.
Divide the first polynomial by the second in each of the following. Also, write the quotient and remainder:
x4 − x3 + 5x, x − 1
Divide the first polynomial by the second in each of the following. Also, write the quotient and remainder:
y4 + y2, y2 − 2
Find whether the first polynomial is a factor of the second.
4x2 − 5, 4x4 + 7x2 + 15
Divide:
x4 − y4 by x2 − y2
Divide 24(x2yz + xy2z + xyz2) by 8xyz using both the methods.
8x3y ÷ 4x2 = 2xy
Simplify `(14"p"^5"q"^3)/(2"p"^2"q") - (12"p"^3"q"^4)/(3"q"^2)`
Divide: (32y2 – 8yz) by 2y