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Divide: 36a3x5 − 24a4x4 + 18a5x3 by − 6a3x3. - Mathematics

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Question

Divide:

36a3x5 − 24a4x4 + 18a5x3 by − 6a3x3.

Sum

Solution

36a3x5 − 24a4x4 + 18a5x3 by − 6a3x3

= `(36"a"^3"x"^5-24"a"^4"x"^4+18"a"^5"x"^3)/(-6"a"^3"x"^3)`

= `(36"a"^3"x"^5)/(-6"a"^3"x"^3)-(24"a"^4"x"^4)/(-6"a"^3"x"^3)+(18"a"^5"x"^3)/(-6"a"^3"x"^3)`

= − 6a3−3 . x5−3 + 4a4−3 . x4−3 − 3a5−3 . x3−3

= − 6a0x2 + 4a1x2 − 3a2x0

= − 6x2 + 4ac − 3a2 ..............(∵ x0 or y0 = 1)

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Concept for Unknowns Through Examples with Simple Contexts (Single Operations)
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Chapter 19: Fundamental Operations (Related to Algebraic Expressions) - Exercise 19 (D)

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Selina Mathematics [English] Class 6
Chapter 19 Fundamental Operations (Related to Algebraic Expressions)
Exercise 19 (D) | Q 5.4
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