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Question
Draw a graph of the equation 2x + 3y + 5 = 0, from the graph find the value of:
(i) x, when y = -3
(ii) y, when x = 8
Solution
We have
2x + 3y + 5 = 0
⇒ 2x + 3y = -5
⇒ 3y = -5 - 2x
⇒ y = `(-2x - 5)/(3)`
When x = -2
⇒ y = `-(1)/(3)` = 0.33
When x = 0
⇒ y = `-(5)/(3)` = -1.66
When x = 2
⇒ y = `-(9)/(3)` = -3
| x | -2 | -1 | 0 | 1 | 2 |
| y | -0.33 | -1 | -1.66 | -2.33 | -3 |
Thus ordered pairs of 2x + 3y + 5 = 0 are {{-2, -0.33), (-1, -1), (0, -1.66), (1, -2.33),(2, -3)}. Hence graph is a below.
(i) x, when y = -3
From graph we find that x = 2, when y = -3
(ii) y, when x = 8
From graph we find that y = -7, when x = 8.
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