Question

Draw the graph of

(i) x – 7y = – 42

(ii) x – 3y = 6

(iii) x – y + 1 = 0

(iv) 3x + 2y = 12

Answer 1

(i) x – 7y = – 42

x	0	7	14
`y=(x+42)/7 `	6	7	8
Points	A	B	C

(ii) x – 3y = 6

x	6	12	18
`y =(x-6)/3 `	0	2	4
Points	D	E	F

(iii) x – y + 1 = 0

      In tabular form

x	0	4
y = x+1	1	5
Points	A	B

(iv) 3x + 2y = 12

x	0	2
`y =(12-13x)/2 `	6	3
Point	C	D

Note:*
(i) The graph of any linear equation is a line and every solution of equations lies on the graph of that equation.
(ii) If a point (a, b) is not on the line then this point is not a solution of given equation.

∵ (2, 9) and (4, 1) are on the line

∴ These two points are solution of given equation

But (1, 10) and (7, –4) are not on the line so these two are not solutions.